Are Promises Lazily Evaluated?

Is the code below guaranteed to output HERE? var p = new Promise(() => console.log('HERE')) (That is, does var p = new Promise(fn) always execute fn if p.then(…) is never cal

Solution 1:

Yes, it is guaranteed. The specification of Promise has this step which will always be evaluated:

9. Let completion be Call(executor, undefined, «resolvingFunctions.[[Resolve]], resolvingFunctions.[[Reject]]»).

where executor is what you passed to the Promise constructor, and Call results in that code being run. This all happens before the Promise is even returned to your p variable.

Solution 2:

As James said, it is guaranteed that the function will be called. Though this doesn't guarantee that the cache entry gets deleted!

You have to check the value of the promise resolution (true if the cache entry is deleted, false otherwise).