Javascript Function Accepting Php Variables

December 23, 2023 Post a Comment

I'm drawing a complete blank why this isn't working. I can do it with one variable passing through, but not two. When I use actually numbers like getnt(1,2) it works. It's just not

Solution 1:

If the ID and pnID are strings, enclose them with brackets like this.

<body><?phpecho"<a href='#' onclick=\"getnt('$nid','$pnid')\">VIEW</a>";
  ?></body>

If still not working, You can debug your code

View the source code in browser, make sure it generates correctly.
Put some alert messages in the javascript function. Install Firebug if you have Firefox or see
Javaascript console if you get any javascript errors.

Solution 2:

You could always try:

<scripttype="text/javascript">functiongetnt(nid,pnid) {
        window.location = "nt.php?nid=" + nid + "&pnid=" + pnid;
    }
</script><body><ahref="#"onclick="getnt(<?phpecho$nid; ?>,<?phpecho$pnid; ?>)">VIEW</a></body>

Solution 3:

Your question is probably best answered by looking at the rendered HTML source.

Baca Juga

In any case, here's how I'd do it using graceful degradation

<scripttype="text/javascript">functiongetnt(element) {
    var href = element.href;
    var nid = element.getAttribute("data-nid");
    var pnid = element.getAttribute("data-pnid");
    returntrue;
}
</script><p><ahref="nt.php?nid=<?phpecho$nid?>&amp;pnid=<?phpecho$pnid?>"data-nid="<?phpecho$nid?>"data-pnid="<?phpecho$pnid?>"onclick="return getnt(this)">VIEW</a></p>

JavaScript General

Javascript Function Accepting Php Variables

Solution 1:

Solution 2:

Solution 3:

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