How To Disable A Submit Button After Submission In PHP?

I browsed through the other questions on this issue but couldn't find a satisfactory answer. I have a quiz website where the user selects an option from four options and then click

Solution 1:

Available Solutions

Since you tagged the question jQuery, here are some simple jQuery solutions you can use:
To disable it when it is clicked, you can simply:

$('input[type="submit"]').click(function() {
    this.disabled = true;
};

You can do even better though, and disable it only once the form is submitted:

$("form").submit(function() {
    $(this).find('input[type="submit"]').prop("disabled", true);
});

Solution Demo

Here's a simple demo of the above logic, in a jsFiddle: http://jsfiddle.net/zb8CZ/
(Note that in that implementation I didn't use jQuery, but rather, plain JS; for portability across browsers however, as well as access to the many other methods jQuery provides (plus the syntactic sugar!) I recommend the jQuery methods.

Good to note...

Note that attempting to implement JS event handling inline in your HTML (using the onsubmit="..." or onclick="..." attributes) is considered bad practice, since it muddles your functionality with your layout/display layer. You also lose any syntax highlighting and/or error-checking your editor might provide, as well as just generally making it harder to develop and maintain your application, since there is no logical order to your code.

Solution 2:

I leave a code:

    <form name="myform" action="/" method="post" onsubmit="document.getElementById('submit_button').disabled = 1;">

<!-- form elements here -->

</form>

Solution 3:

For disable write like this, after once click it will be disable.

<input type="submit" id="but_sub" name="submit" \>


    $("#but_sub").click(function() {
        $(this).attr("disabled",true);
    }

or

    $('#but_sub').click(function() {
        $(this).attr("disabled","disabled");
    }

Solution 4:

Try this. You might want to pass the value of each answer to a PHP file that performs backend work via AJAX.

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js" ></script>
<script>
    $('#question').submit(function(){
       //Get the value of the answer that was checked
       var answer = $('input:radio[name=question_one]:checked').val();

       //Use jQuery's AJAX function to send the data to a PHP file that does backend work 
       $.ajax({  
          type:'POST',  
          url:'quiz_backend.php',  
          data:'answer='+ answer,
          success: function() {
              //Hide the submit button upon successful submission
              $('#submit').attr("disabled", true);
              event.preventDefault();
          }
       });
    });
</script>

<form id="question">
   <input type="radio" name="question_one" value="answer_one">A<br />
   <input type="radio" name="question_one" value="answer_two">B<br />
   <input type="radio" name="question_one" value="answer_three">C<br />
   <input type="radio" name="question_one" value="answer_four">D<br />

   <input type="submit" value="submit" id="submit"/>
</form>

More info about jQuery's AJAX call here.

Solution 5:

very easy javascript only method

<form action="" method="post" >
<input type="submit" name="SUBMIT" value="Submit Form"
   onclick="this.disabled='disabled';this.form.submit();" />
</form>