Skip to content Skip to sidebar Skip to footer

Why Is Typeof's Result Different Than The Evaluated Result Of The Expression Passed In?

If two Objects added together equal NaN(not a number), which is technically of type number, then why does getting the type of two Objects added together result in 'string'? I will

Solution 1:

{} + {} is an empty block ({}) followed by a type conversion from object to number (+{}). It basically reads as

{} // empty block (a statement)
;  // empty statement (just for clarity)
+{}; // expression statement (unary plus, object literal -> conversion to number)

However if you use typeof ({} + {}), then {} + {} will be evaluated as expression in which case both {} can only be object literals and the + is the concatenation operator.

You can also just use the grouping operator to force the construct to be evaluated as expression:

({} + {}) // expression statement (string concatenation with two objects)

See also Why {} + {} is NaN only on the client side? Why not in Node.js? and other questions related to [javascript] "{} + {}".


Post a Comment for "Why Is Typeof's Result Different Than The Evaluated Result Of The Expression Passed In?"